Spreadsheet: Fix SheetPython::getViewProviderName() to return the correct type name
For more details see: https://forum.freecad.org/viewtopic.php?t=88642
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@@ -1785,7 +1785,7 @@ PROPERTY_SOURCE_TEMPLATE(Spreadsheet::SheetPython, Spreadsheet::Sheet)
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template<>
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const char* Spreadsheet::SheetPython::getViewProviderName() const
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{
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return "SpreadsheetGui::ViewProviderSheet";
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return "SpreadsheetGui::ViewProviderSheetPython";
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}
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template<>
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PyObject* Spreadsheet::SheetPython::getPyObject()
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